Answer by Gecko for How can I partition (split up, divide) a list based on a condition?

I think a generalization of splitting a an iterable based on N conditions is handy

from collections import OrderedDictdef partition(iterable,*conditions):'''Returns a list with the elements that satisfy each of condition.       Conditions are assumed to be exclusive'''    d= OrderedDict((i,list())for i in range(len(conditions)))            for e in iterable:        for i,condition in enumerate(conditions):            if condition(e):                d[i].append(e)                break                        return d.values()

For instance:

ints,floats,other = partition([2, 3.14, 1, 1.69, [], None],                              lambda x: isinstance(x, int),                               lambda x: isinstance(x, float),                              lambda x: True)print " ints: {}\n floats:{}\n other:{}".format(ints,floats,other) ints: [2, 1] floats:[3.14, 1.69] other:[[], None]

If the element may satisfy multiple conditions, remove the break.